I think I speak for most people when I say that I’m a good representative of the general population.

  • 0 Posts
  • 7 Comments
Joined 5 years ago
cake
Cake day: June 29th, 2020

help-circle
  • Soda hits a spot that sugary drinks without the fizz don’t. It’s why sodas taste awful when they’ve gone flat. If I buy one of those prepackaged sweet teas I can’t handle it, the sweetness is somehow overpowering for me. Same goes for most juices.

    For me, sugar really brings out the flavor in things though. The sugar in a soda works to enhance the flavor, while the carbonation offsets the strength of the sugar. If I water down a soda with seltzer it’s okay, but it’s much more bland, so much less enjoyable. It really is the combination of the two that works here.

    With that said, I am pretty picky with my sodas (much like everything else I’m eating or drinking, unfortunately). Anything I don’t enjoy much more than water I’ll turn down. I like colas and birch beers and cream sodas, not so much orange/grape soda or sprite.





  • If you want to show there are infinitely many primes, one way is to first note that every integer greater than 1 has a prime factor. This is because if an integer n is prime, n is a prime factor of itself, and if n is not prime then it must have a smaller factor m other than 1, 1< m < n. If m is also not prime, it too must have a smaller factor other than 1, and you can keep playing this game but there are only so many integers between 1 and n so eventually you’ll get to a factor of n that has no smaller factors of its own other than 1, which means it is prime.

    Let’s now suppose there is only a finite number of primes, we’ll try to show that this assumption leads to nonsense so can’t be possible.

    We can multiply any finite number of integers together to get a new integer. Let’s multiply all of the primes together to get a new number M. Then M + 1 gives a remainder of 1 when you divide by any prime number. Since dividing by a factor will always give a remainder of 0, none of the prime numbers can be a factor of M + 1. So M + 1 is an imteger bigger than 1 with no prime factors. This is impossible, so there must be a mistake somewhere in this argument.

    The only thing we said that we’re not 100% sure is true was that there are a finite number of primes, so that has to be our mistake. So there must be infinitely many prime numbers.